Solve the following pair of linear equations | vedclass

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(D) Given equations are:$1) 8x - 3y = 1$$2) 34x - 3y = 14$From equation $(1)$,we can express $3y$ as:$3y = 8x - 1$$y = (8x - 1) / 3$Substitute this va

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$(1/2, 1)$

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(D) Given equations are:$1) 8x - 3y = 1$$2) 34x - 3y = 14$From equation $(1)$,we can express $3y$ as:$3y = 8x - 1$$y = (8x - 1) / 3$Substitute this value of $y$ into equation $(2)$:$34x - 3((8x - 1) / 3) = 14$$34x - (8x - 1) = 14$$34x - 8x + 1 = 14$$26x = 13$$x = 13 / 26 = 1/2$Now,substitute $x = 1/2$ into the expression for $y$:$y = (8(1/2) - 1) / 3$$y = (4 - 1) / 3$$y = 3 / 3 = 1$Thus,the solution is $(x, y) = (1/2, 1)$.

Solve the following pair of linear equations by the method of substitution: $8x - 3y = 1$ and $34x - 3y = 14$.

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